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Height of tide and depth of water

It tells you how much water there is under the boat at a given time, and when there is enough to pass or enter.

Types of exercise

How it works

Start from the day's table of the standard port, which gives time and height of high water (HW) and low water (LW). You need three numbers: the duration (time from LW to HW, about six hours but worked out), the range (HW − LW) and the tidal hour (duration ÷ 6). Example, Colville: LW 09:25 at 0.8 m, HW 15:31 at 4.4 m. Duration 6 h 06 min = 366 min; range 4.4 − 0.8 = 3.6 m; tidal hour 366 ÷ 6 = 61 min.

Height at a given time, with the rule of twelfths: in the six tidal hours the level moves by 1, 2, 3, 3, 2, 1 twelfths of the range, so the running totals are 1, 3, 6, 9, 11, 12. Height at 12:31: since LW 3 h 06 min = 186 min = 3.05 tidal hours have passed. At 3 hours it has risen 6/12; in the 3 minutes after, a little more: about 0.51 of the range. Height = 0.8 + 0.51 × 3.6 = 2.6 m.

Time for a given height: reverse the calculation. When does the tide rise to 3.0 m? You need 3.0 − 0.8 = 2.2 m out of 3.6, that is 2.2 ÷ 3.6 × 12 = 7.3 twelfths. The running totals say 6 at the end of the third hour and 9 at the end of the fourth: you are in the fourth hour, (7.3 − 6) ÷ 3 = 0.44 of the way through. That is 3.44 tidal hours × 61 min = 210 min = 3 h 30 min after LW. Time: 09:25 + 3:30 = 12:55.

Depth of water = charted depth + height of tide, because the chart measures from Chart Datum. With 2.4 m charted and tide 2.6 m: 5.0 m. If the seabed dries, the chart gives a drying height and you subtract: tide − drying height. A rock drying 0.5 m with tide 2.6 m: 2.1 m of water. The under keel clearance is depth of water − draught: with a draught of 1.8 m, 5.0 − 1.8 = 3.2 m.

How much tide do you need to cross a shallow spot? Water needed = draught + safety clearance: 1.8 + 0.5 = 2.3 m. Height of tide required = water needed − charted depth: with 0.5 m charted, 2.3 − 0.5 = 1.8 m. Rise from 0.8 to 1.8 m: 1.0 out of 3.6 = 3.3 twelfths, 0.11 into the third hour: 2.11 hours × 61 = 129 min, at 11:34. With the tidal curve it comes out near 11:38: a few minutes' difference is normal. If the spot dries: required = needed + drying height.

A secondary port has no tables: take the time and height of the standard port and apply the almanac differences. If the standard port time falls between two columns of the block, interpolate, never extrapolate. Example, Jackson Bay from Colville: HW 15:31 lies between 13:00 (−65 min) and 19:00 (−5 min). 151 min out of 360 have passed since 13:00: −65 + 151 ÷ 360 × 60 = −40 min, so HW at Jackson Bay is at 14:51. Heights are treated the same way, between MHWN and MHWS: 4.4 m + 0.3 m = 4.7 m. At the end, if needed, correct for daylight saving.

Common mistakes

  • Getting the running twelfths wrong: the third hour adds 3/12 and takes you to 6/12, not 3/12. Write 1, 3, 6, 9, 11, 12 before you start.
  • Using twelfths where the tide is irregular (for example the double high water in the Solent) or always assuming 6 hours: the duration must be worked out for the day.
  • Adding the height of tide to a drying height: for a drying seabed you subtract, and a negative result means the spot is out of the water.
  • Extrapolating instead of interpolating the secondary port differences, or forgetting the time zone and daylight saving: the tables are in standard time, the boat lives on local time.
  • Trusting the figure to the centimetre: the rule is approximate and strong wind or pressure changes the real height (about 1 cm per hPa). Always leave a safety margin.

Exercises from the course book

9 exercises from the school's material, each solved step by step with the reason and the formula.

Esercizi d'esame del corso

Gli esercizi del libro, con la curva di marea del porto: come li trovi all'esame.